Question

please solve it ques no. 6th.

Class 10th

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Answer 1

let A has x students and B has y student
Now ATQ
x-10=y+10
x-y=20
2(y-20)=x+20
2y-40=x+20
x-2y=-60
-x+2y=60
x-y=20
on adding the eq. we get
y=80=B
x=20+y=20+80=100 =A

Answer 2

hey !!!!

here is your answer,

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Let the number of students in hall a=x

and number of students in hall b=y

1. When we send 10 students from hall a to b:

Number of students left in hall a=x-10

and Number of students in hall b=y+10

And, in this case number of student in each hall would be equal, so we get:

$x - 10 = y + 10 \\ x - y = 20 \: \: \: \: - - - - - (1)$


2. When 20 students are sent from b to a:

Number of students in hall a=x+20

and Number of students in hall b=y-20

In this case number of students in hall a becomes double the number of students in hall b,so we get:

$x + 20 = 2(y - 20) \\ x + 20 = 2y - 40 \\ x - 2y = - 60 \: \: \: \: \: - - - - - (2)$


By subtracting (2) from (1) we get:

$y = 80$
$and \: x - y = 20$
$= > x - 80 = 20 \\ = > x = 100$


So there are 100 students in hall a and 80 students in hall b.


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HOPE IT HELPS U !!!

CHEERS :))

# NIKKY