Math, asked by shreya264, 1 year ago

please solve it question 5 and 6

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Answered by sanjayharsh112p8wsus
2
This is your answer see it okkkkkkkkkkkkkkkkk
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shreya264: a square b square upon ab kese kiya
sanjayharsh112p8wsus: LCM le ke
shreya264: ok
sanjayharsh112p8wsus: Ok
Answered by HimanshuR
0
Q no. 5)
p(x) = x + 4 \\ p( - x) =  - x + 4 = 4 - x \\ p(x) + p( - x) = x + 4 + 4 - x \\ p(x) + p( - x) = 8
Q no. 6)
if \:  \frac{a}{b}  +  \frac{b}{a}  =  - 1 \\ then \: a {}^{2}  + b {}^{2}  + ab = 0 \\ we \: know \: that \\ a {}^{3}  - b {}^{3}  = (a - b)(a {}^{2}  + b {}^{2}  + ab) \\  = (a - b) \times 0 = 0 \\ so  \: \: a {}^{3}  - b {}^{3}  = 0
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