Question

please solve it quickly.
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Answer 1

Answer:

3) BA^2 sin@ cos@

Explanation:

( B × A ).A

= ( BA sin@).A

= BA^2 sin@ cos @

REMEMBER :

A × B = ABsin@

A.B = ABcos@

THANKS

Answer 2

Answer:

(3)BA^sin@cos@

Explanation:

1)B×[email protected]

magnitude of B×A=ABsin@

Therfore,

As

magnitude of B.A=ABcos@

[email protected]@

=BA^sin@cos@