Math, asked by padhiarvidhi79, 10 months ago

please solve it quickly​

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Answered by Anonymous
1

Answer:

Step-by-step explanation:

a = (√10+√5)/(√10-√5)

  = (√10+√5)/(√10-√5)×(√10+√5)/(√10+√5)

  = (10+5+10√2)/10-5 = (15+10√2)/5

  = 5(3+2√2)/5

  = 3+2√2

b = (√10-√5)/(√10+√5)

  = (√10-√5)/(√10+√5)×(√10-√5)/(√10-√5)

  = (10+5-10√2)/10-5 = (15-10√2)/5

  = 5(3-2√2)/5

  = 3-2√2

√a-√b-2√ab

= √(3+2√2)-√(3-2√2)-2√(3+2√2)(3-2√2)

= √(2+1+2√2)-√(2+1-2√2)-2×(3-2√2)

= √2+1-√2+1-6+4√2

= 0

Answered by siddharth0130
5

Step-by-step explanation:

√a

(√10+√5)×(√10+√5)/(√10-√5)×(√10+√5)=

ans of [A]10+√50+5/10-5

√b

(√10-√5)×(√10-√5)/(√10+√5)×(√10-√5)=

ans of [B]10-√50-5/10-5

ans of √a-√b=. 0/5there for ans is o

&

√a×√b. is also 0

so ans. is 0

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