please solve it quickly
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Answered by
1
Answer:
Step-by-step explanation:
a = (√10+√5)/(√10-√5)
= (√10+√5)/(√10-√5)×(√10+√5)/(√10+√5)
= (10+5+10√2)/10-5 = (15+10√2)/5
= 5(3+2√2)/5
= 3+2√2
b = (√10-√5)/(√10+√5)
= (√10-√5)/(√10+√5)×(√10-√5)/(√10-√5)
= (10+5-10√2)/10-5 = (15-10√2)/5
= 5(3-2√2)/5
= 3-2√2
√a-√b-2√ab
= √(3+2√2)-√(3-2√2)-2√(3+2√2)(3-2√2)
= √(2+1+2√2)-√(2+1-2√2)-2×(3-2√2)
= √2+1-√2+1-6+4√2
= 0
Answered by
5
Step-by-step explanation:
√a
(√10+√5)×(√10+√5)/(√10-√5)×(√10+√5)=
ans of [A]10+√50+5/10-5
√b
(√10-√5)×(√10-√5)/(√10+√5)×(√10-√5)=
ans of [B]10-√50-5/10-5
ans of √a-√b=. 0/5there for ans is o
&
√a×√b. is also 0
so ans. is 0
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