PLEASE solve it quickly.
if cos A = 21/29 , find the value of sin A + tan A
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sin2A + Cos2A = 1
sin A = √1- cos2A
sin A = √ 1- (21/29)^2
sin A = ( 29^2 - 21^2 / 29^2 )
sin A = √400 / 29^2
sin A = 400 / 29 = 20 / 29
tan A = sin A / cos A
tan A = 20/29 / 21 /29
tan A = 20/ 21
sin A + tan A = 20/29 + 20/ 21
= 1.64 Ans .
sin A = √1- cos2A
sin A = √ 1- (21/29)^2
sin A = ( 29^2 - 21^2 / 29^2 )
sin A = √400 / 29^2
sin A = 400 / 29 = 20 / 29
tan A = sin A / cos A
tan A = 20/29 / 21 /29
tan A = 20/ 21
sin A + tan A = 20/29 + 20/ 21
= 1.64 Ans .
anshika321:
thanks
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