Question

please solve it's urgent​

Answer 1

Given,

$\green\succ\rm{Length\: of\: the\: reservoir\: = 120m}$

$\green\succ\rm{Breadth\: of\: the \:reservoir\: = 75m}$

$\green\succ\rm{The\: height\: of\: the\: water\: level\: in\: 9 \:hours\: = 1.2 m}$

Solution,

Volume of the water collected in the reservoir 120 × 75 × 1.2  = 10,800 m³

Let,

The speed of the flowing water = x m/hr.

(A.T.Q)The water flowing in the pipe eventually forms a cuboid of width 20 cm or 0.2 m and height of 20 cm or 0.2m.

So,

The length of the cuboid so formed in the pipe in 9 hours = 9x m

Therefore,

The volume of the water flows out of the pipe in 9 hours

$\red\implies\tt{0.2 \times 0.2 \times 9x}$

$\red\implies\tt{0.36x m^3}$

Volume of the water collected in the reservoir = volume of the water flows out of the pipe in 9 hours.

$\purple:\longmapsto\sf{10800 = 0.36x}$

$\purple:\longmapsto\sf{x = \frac{10,800}{0.36}}$

$\purple:\longmapsto\sf{x = 30,000 m/hr}$

Or, speed of the water = 30 km/hr.

Hope it helps:)