Please solve It's Urgent!!!!!!
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ATMQ:
the exterior sum of a quadrilateral is 360 degrees...
so it will be 66a+27a+31a+56a=360 degree
= 180a=360
a=360/180
a=2
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Sum of all exterior angles of a polygon is 360°
27a° + 66a° + 56a° + 31a° = 360°
180a° = 360°
a° = 360÷180
a° = 2
27a° + 66a° + 56a° + 31a° = 360°
180a° = 360°
a° = 360÷180
a° = 2
Answered by
0
1.The exterior sum of a quadrilateral
is 360 degrees
2.so it will be
66a+27a+31a+56a= 360
=180a=360
a= 360/180
a=2
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