Question

Please solve it's urgent and no spams or else...... and who will give the correct answer wid full explanation before 5:00 I will mark as the brainliest. ​

Answer 1

$\huge\sf\blue{Given}$

✭ ∆ABC & ∆DBC are two isosceles triangles

✭ AD is produced to meet at point P

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$\huge\sf\gray{To \: Prove}$

◈ ∆ABD ≅ ∆ACD

◈ ABP ≅ ∆ACP

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$\huge\sf\purple{Steps}$

☯ $\sf \underline{\sf As \ Per\ the \ Question}$

◕ AB = AC

◕ BD = DC as the given triangles are isosceles

So in ∆ADB & ∆ACD

➝ $\sf AB = AC$ «« Isosceles Triangle »»

➝ $\sf AD = AD$ «« Common »»

➝ $\sf BD = DC$ «« Isosceles Triangle »»

$\sf \therefore$ ∆ADB ≅ ∆ACD ««« SSS »»»

Similarly in ∆ABP & ∆ACP

➳ $\sf AB = AC$ «« Isosceles Triangle »»

➳ $\sf \angle ABP = \angle ACP$ «« Angles opposite to equal sides are equal

➳ $\sf AP = AP$ «« Common »»

$\sf \therefore$ ∆ABP ≅ ∆ACP ««« SAS »»»

$\sf Hence \ Proved!!$

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Answer 2

✭ ∆ABC & ∆DBC are two isosceles triangles

✭ AD is produced to meet at point P

━━━━━━━━━━━━━

◈ ∆ABD ≅ ∆ACD

◈ ABP ≅ ∆ACP

━━━━━━━━━━━━━

☯  

◕ AB = AC

◕ BD = DC as the given triangles are isosceles

So in ∆ADB & ∆ACD

➝  «« Isosceles Triangle »»

➝  «« Common »»

➝  «« Isosceles Triangle »»

∆ADB ≅ ∆ACD ««« SSS »»»

Similarly in ∆ABP & ∆ACP

➳  «« Isosceles Triangle »»

➳  «« Angles opposite to equal sides are equal

➳  «« Common »»

∆ABP ≅ ∆ACP ««« SAS »»»

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