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Two points are located at A(-4,4) and B(5,3). For two points P, Q on the x-axis and R on the line y=1, find the minimum value of AP+PR+RQ+QB.
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When R is reflected. (Image 1)
Reflect against -axis. Let the image be R'.
Adding two inequalities
When has its minimum value. (Image 2)
If all the points are moved to each location
Again, if B' is moved to
So, the minimum of is equal to .
Finding the minimum length. (Image 3)
For the two points and , the length is . Hence the minimum length is .
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Answer:
Solution :
When R is reflected. (Image 1)
Reflect R(a, 1) against x -axis. Let the image
be R'.
PR= PR', RQ = RQ'
AP+ PR = AP + PR'
AR'.
[1]
⇒RQ+QB = R'Q+QB > RB'
[2]
Adding two inequalities
..AP+PR+RQ+QB ≥ AR' + R'B
When AR' + R'B has its minimum value.
(Image 2)
If all the points are moved to each location
Again, if B' is moved to B" (5,-4)
A'(-4,5), B'(5,4), R" (a,0)
AR+R'B≥ A'R" + R"B'
A'R"R"B"
A'R" + R"B" > A'B"
So, the minimum of AP +PR+RQ+QB is equal to A'B" .
Finding the minimum length. (Image 3)
For the two points A'(-4,5) and B" (5,-4),
the length is 9√2. Hence the minimum
length is 9√/2.
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