Math, asked by J1TENDRA, 10 months ago

PLEASE SOLVE IT STEP BY STEP​

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Answered by myiitgoal2122
2

Answer:

Step-by-step explanation:

loga^2/ab+logb^2/bc+logc^2/ac

We know that loga+logb=logab

Applying this we get

log a^2*b^2*c^2/ab*bc*ac

=log1

We know that log1 to the base any thing is 0

Hence proved

Plz mark me as brainliest

Answered by Anonymous
7

Answer:

Hello Dear User__________

Here is Your Answer...!!

____________________

Explanation:Answer:

Given \ log\frac{a^{2} }{bc}+ \ log\frac{b^{2} }{ca} \ log\frac{c^{2} }{ab}=0\\\\we \ have \ to \ prove \ it\\\\Here\ we \ have \ to \ use \ formula \ log\frac{a}{b}=log \ a-log \ b\\ \\log \ (mn)=log \ m+log \ n\\\\loga^{b}=b \ log \ a\\\\coming \ back \ to \ question.\\\\2log \ a-log \ bc+2log \ b-log \ cal+2og \ c-log \ ab\\\\2log \ a-log \ b-log \ c+2log \ b-log \ c-log \ a+2log \ c-log \ a-log \ b\\\\2log \ a+2log \ b+2log \ c-2log \ a-2log \ b-2log \ c\\ \\0\\\\Hence \ proved.

Hope it is clear to you.

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