please solve it step by step
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sin^-1x -cos^-1x = pi/6
since, sin^-1x = pi/ 2 - cos^-1x
Putting in 1st Equation
sin-1x+ cos^-1x-2cos^-1x = pi/6
pi/2 - 2cos-1x = pi/6
pi/3= 2cos^-1x
pi/6 =cos^-1x
x= cos (pi/6)
x= Root 3 /2
hope it helps!!!
since, sin^-1x = pi/ 2 - cos^-1x
Putting in 1st Equation
sin-1x+ cos^-1x-2cos^-1x = pi/6
pi/2 - 2cos-1x = pi/6
pi/3= 2cos^-1x
pi/6 =cos^-1x
x= cos (pi/6)
x= Root 3 /2
hope it helps!!!
Sohasree45:
sorry bt u have done a silly mistake to see the question,,here it was sin^-1-cos^-1=pi/6..so please can u answer the correct question?
what is wrong in it i am not able to make out
the qusetion was sin^-1x-cos^-1x=pi/6..bt u did sin^-1x+cos^-1x=pi/6..please check it..
oops sorry..this was my mistake..bt thank you..
ur welcome
(^_-)(^_-):);)
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