Question

please solve it
step by step​

Answer 1

Figure regards this question:

$\setlength{\unitlength}{1mm}\begin{picture}(7,2)\thicklines\multiput(7,2)(1,0){55}{\line(3,4){2}}\multiput(35,7)(0,4){12}{\line(0,1){0.5}}\put(10.5,6){\line(3,0){50}}\put(35,60){\circle*{12}}\put(37,7){\large\sf{u = 20 m/s}}\put(37,55){\large\sf{v = 0 m/s}}\put(21,61){\large\textsf{\textbf{Ball}}}\put(43,40){\line(0, - 4){28}}\put(43,35){\vector(0,4){18}} {\pmb{\sf{BrainlyButterfliee}}}\put(24, - 3){\large\sf{ \sf g = -9.8 \: m/s^2 }}\put(48,30){\large\sf{T = ?}}\end{picture}$

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Question:

A ball is thrown vertically upward with an initial velocity of 20 mps. What is the time taken by the ball to return the ground!?

Provided that:

• Initial velocity = 20 mps
• Final velocity = 0 mps
• g = -9.8 mps sq.

Don't be confused!

• Final velocity cames as zero because the ball is thrown upwards as it will stop for a while at the highest point.

• We take g as negative because the ball is thrown upwards means against gravity.

To calculate:

• Time taken

Solution:

• Time taken = 2.04 seconds

Using concept:

• First equation of motion

Using formula:

• v = u + at

Where, v denotes final velocity, u denotes initial velocity, a denotes acceleration and t denotes time taken.

Required solution:

»»» v = u + at

»»» 0 = 20 + (-9.8)(t)

»»» 0 - 20 = -9.8t

»»» -20 = -9.8t

»»» 20 = 9.8t

»»» 20/9.8 = t

»»» 2.04 = t

»»» t = 2.04 sec

»»» Time taken = 2.04 sec

Additional information:

Difference between Gravitation and gravity is mentioned:

$\begin{gathered}\boxed{\begin{array}{c|cc}\bf Gravitation &\bf Gravity\\\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}&\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}\\\sf It \: is \: that \: attracting \: force &\sf Force \: of \: gravity \: is \: gravitation \: pull \: on \: a \: body \\ \sf applied \: between \: any \: 2 \: bodies \: of \: universe &\sf \: near \: or \: on \\ &\sf \: the \: surface \: of \: the \: earth \\ \\ \sf It \: is \: a \: universal \: force & \sf It \: isn't \: a \: universal \: force \\ \\ \sf Gravitation \: is \: attracting \: force & \sf Gravity \: is \: a \: pulling \: force \\ \\ \sf Gravitation \: is \: a \: weak \: force & \sf It \: isn't \: weak \: as \: gravitation \\ \\ \sf G \: is \: symbol \: for \: gravitation & \sf g \: is \: symbol \: for \: gravity \\ \\ \sf G \: = \dfrac{Fd^2}{Mm} & \sf g \: = \dfrac{GM}{R^2} \end{array}} \end{gathered}$

Answer 2

✠ Question :-

A ball is thrown vertically upward with an initial velocity of 20 mps. What is the time taken by the ball to return the ground ?

✠ Answer :-

• The time taken by ball = 2.04 sec .

✠ Explanation :-

⟶ Given :-

• Initial Velocity = 20 mps
• Final Velocity = 0 mps
• G = -9.8 mps sq .

⟶ To Find :-

• The time taken by ball to return ?

⟶ Solution :-

• ★ Using First Equation of Motion .

⠀⠀⠀⠀⠀⠀⠀$\sf \pink{v = u + at} \\ \\ \small \sf{0 =20 + ( - 9.8) \: t } \\ \\ \small \sf{0 - 20 = - 9.8 \: t} \\ \\ \small \sf{20 = - 9.8 \: t} \\ \\ \small \sf{t = \cancel \frac{20}{9.8} } \\ \\ \Longrightarrow \underline{\small \sf \pink{t = 2.04 \: sec}}$

⟶ Hence :-

• The time taken by ball = 2.04 sec

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✠ Learn More :-

⠀⠀⠀$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf\bigstar\: \: {Three \: equations\: of \: motion}}} \\ \\ \sf 1.] \:\: v \: = u \: + at \\ \\ \sf 2.]\:\: s \: = ut + \: \dfrac{1}{2} \: at^2 \\ \\ \sf 3.] \:\: v^2 - u^2 \: = 2as\end{array}}\end{gathered}\end{gathered}$

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