Question

please solve it
$| 1 + \frac{6x + 1}{3} = \frac{x - 3}{6}$
solve it​

Answer 1

$1 + \frac{6x + 1}{3} = \frac{x - 3}{6} \\ \frac{3 + 6x + 1}{3} = \frac{x - 3}{6} \\ \frac{4 + 6x}{3} = \frac{x - 3}{6} \\ 24 + 36x = 3x - 9 \\ 33x = - 33 \\ x = - 1$