Question

please solve it the answer is K/2r

Answer 1

Given that the object of mass m is moving in a circular path under a centripetal force

Here, we are given that the centripetal force is

k/r²

But we know that centripetal force =

mv²/r

So, equating the two values, we get

k/r² = mv²/r

$\frac{ {mv}^{2} }{r} = \frac{k}{ {r}^{2} } \\ \\ = > {mv}^{2} = \frac{k}{ {r}^{2} } \times r \\ \\ = > m {v}^{2} = \frac{k}{r}$


Now we got that mv² = k/r


We have to find kinetic energy

We know that, kinetic energy =


1/2 mv²

But mv² = k/r

=> kinetic energy = 1/2 × k/r

= k/2r



Hope it helps dear friend ☺️