Question

please solve it. the options are given.​

Answer 1

Solution: Volume of cone = ⅓ πr²h

(In case of whole cone as per diagram)

• radius = r₂
• height = 2h [bcz AO = OP = h]

(In case of small cone as per diagram)

• radius = r₁
• height = h [bcz AO = h]

→ Ratio = ⅓πr₁²h/(⅓πr₂² × 2h)

→ Ratio = r₁²/2r₂² __(i)

Now in ∆AOD & ∆APB we have,

→ ∠AOD = APB [90° each]

→ ∠DAO = BAP [Common]

By AA Critera of similarity, ∆AOD ~ ∆APB

→ AO/AP = OD/BP

→ h/2h = r₁/r₂ → r₁/r₂ = ½

Coming onto equation (i)

→ Ratio = (r₁/r₂)² × ½

→ Ratio = (½)² × ½

→ Ratio = 1:8 (OPTION D)

Answer 2

I do not get it

Please check the answer

May be it is the ans