Math, asked by foram70, 10 months ago

please solve it this 2 questions​

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Answers

Answered by kobietten20061995
1

Step-by-step explanation:

2.a)(x−6)(x+7)=(x+3)(x−11)

Step 1: Simplify both sides of the equation.

x^2+x−42=x^2−8x−33

Step 2: Subtract x^2 from both sides.

x^2+x−42−x^2=x^2−8x−33−x^2

x−42=−8x−33

Step 3: Add 8x to both sides.

x−42+8x=−8x−33+8x

9x−42=−33

Step 4: Add 42 to both sides.

9x−42+42=−33+42

9x=9

x=1

b)(x+7)(x+9)=(x+3)(x+21)

x^2+9x+7x+63=x^2+21x+3x+63

x^2+16x+63=x^2+24x+63

x^2+16x+63-x^2-24x-63=0

16x-24x=0

-8x=0

x=0:(-8)

x=0

c)(x+1)(x+2)=(x-3)(x-4)

x^2+3x+2=x^2-7x+12

x^2+3x+2-x^2+7x-12=0

10x-10=0

10x=0+10

10x=10

x=1

d)(x+2)/(x+5)=x/(x+6)

(x+2)(x+6)=x*(x+5)

x^2+8x+12=x^2+5x

x^2+8x+12-x^2-5x=0

3x+12=0

3x=-12

x=-4

e)(5x-7)/(3x+1)=1

5x-7=1*(3x+1)

5x-7=3x+1

5x-7-3x-1=0

2x-8=0

2x=8

x=8/2

x=4

f)(3x-8)/(2x-5)=1/3

(3x-8)*3=(2x-5)*1

9x-24=2x-5

9x-24-2x+5=0

7x-19=0

7x=19

x=19/7

g)(5x+2)/(x-3)=-9/4

(5x+2)*4=(x-3)*(-9)

20x+8=-9x+27

20x+8+9x-27=0

29x-19=0

29x=19

x=19/29

h)3/(x-1)-2/(x-2)=1/(x-3)

((3(x-2)-2(x-1))/((x-1)(x-2))=1/(x-3)

(3X-6-2x+2)/(x^2-3x+2)=1/(x-3)

(x-4)/(x^2-3x+2)=1/(x-3)

(x-4)*(x-3)=(x^2-3x+2)*1

x^2-7x+12=x^2-3x+2

x^2-7x+12-x^2+3x-2=0

-4X-10=0

-4x=10

x=10/(-4)

x=5/2

i.x/3+7=2x/3+2

1x/3-2x/3=2-7

-1x/3=-5

-x=-5*3

-x=-15

x=15

j.x/3-7=2x/3+2

x/3-2x/3=2+7

-x/3=9

-x=9*3

-x=27

x=-27

k.(m-17)/2=2m-7

m-17=(2m-7)*2

m-17=4m-14

m-4m=-14+17

-3m=3

m=3/(-3)

m=-1

l/7-x=(2x-7)/5

(2x-7)/5=7-x

2x-7=(7-x)*5

2x-7=35-5x

2x-7-35+5x=0

7x-42=0

7x=0+42

7x=42

x=42/7

x=6

m.x/2-(x-4)/6=5/3

((x*6)-2(x-4))/2*6=5/3

6x-2x+8=5/3*12

6x-2x+8=20

4x=20-8

4x=12

x=3

3.

10-y=y-10

10+10=y+y

20=2y

20/2=y

10=y

Answered by tejalshah87
1

Answer:

2a x =1

b x = 0

c x = 1

d x = -4

e x = 2

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