please solve it
tommorow is my exam
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sahildhande987:
Bhai exam parso hai
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Answered by
3
Before coming on to the question you must know that=R=ρl/A
where
ρ=Specific reistance or resistivity
l=lenght of resistor
A=cross section of resistor
According to question, l=1 m, diameter=0.3 mm=3*10^-4 m, R=26Ω
ρ=RA/l
=Rπd²/4l [We have taken 4l because area is πr² or πd²/4]
=26*π*9*10^-8/4
=1.84*10^-6 Ωm
the resistivity of the metal at 20 degrees is 1.84*10^-6 which is manganese if you look at the table on the page no.207
4L kyu aaya bataya hi nahi bhai
because area is πd²/4 so substituting in the equation we get
πd²/4/L and then πd²/4*1/L which is πd²/4l
πd²/4/L and then πd²/4*1/L which is πd²/4l
Phir bhi ghanta pata nahi chal raha isse 4L kaise aaya to
Hii harsh woh full ho gaya. Kal se yahan bhejna
Byy
yha nhi
vo me bataunga
Answered by
5
πd²=πr²+πr²
πd²=π(r²+r²)=π(d/2)²
πd²/4L
Thank you
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ye to mere pas bhi tha
but thanks for help
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