Question

please solve it tomorrow is my exam ​

Answer 1

Explanation:

Heya User:-

Given:

$\frac{ {2}^{3} \times {5}^{x + 1} \times {10}^{2} \times {5}^{x - 1} }{125 \times {5}^{x - 2} \times {2}^{7} }$

$\frac{ {5}^{x + 1} \times 4 \times {5}^{x - 1} }{ {5}^{x - 2} \times {2}^{4} }$

$\frac{ {5}^{x + 1} \times {5}^{x - 1} }{8 \times {5}^{x - 2} }$

$\frac{ {5}^{2x} }{8 \times {5}^{x - 2} }$

$\frac{ {5}^{2x - x + 2} }{8}$

$\frac{ {5}^{x + 2} }{8}$

${5}^{x + 2} = {0}^{1}$

$they \: are \: equal \: \\ so \: we \: can \: equate \: powers$

$x + 2 = 1$

$x = - 1$

$hope \: it \: helps$