Math, asked by nirajlazade0711, 9 months ago

please solve it urgently

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Answered by 5oumy4j17

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Answer:

See Explanation

Step-by-step explanation:

6)a) ∠1= ∠DBC

b) ∠2= ∠EBD

c) ∠3= ∠ABE

d) ∠1+∠2= ∠DBC+∠EBD= ∠EBC

e) ∠2+∠3= ∠EBD+∠ABE= ∠ABD

f) ∠1+∠2+∠3= ∠DBC+∠EBD+∠ABE= ∠ABC

g) ∠CBA-∠1= ∠CBA-∠CBD= ∠ABD

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