please solve it urgently
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given
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AB||CD
/_BAD=57°
/_ECD=30°
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FIND
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/_DEC=/_x=??
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solve
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when AB||CD and AD transversal
/_BAD=/_EDC=57°(alternate angle)
in ∆ECD
/_EDC+/_DEC+/_ECD=180° (∆trangle total angle)
57°+x+30°=180°
x=180°-87°=93°
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x=93°
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I hope it helps plz mark as brainlist
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