Question

please solve it urgently ​

Answer 1

ANSWER

$6.25\times {10}^{11}$

Step By Step Explanation

Given,

Q = $1\times {10}^{-7}c$

Let `n`be the total number of electrons present in the metal.

and charge of one electron be =>

e = $1.6 \times {10}^{-19}$ c

Now,by using formula we know that =>

Q = $n\times e$

=>n = $\dfrac{Q}{e}$

=>n = $\dfrac{ 1\times {10}^{-7} }{ 1.6 \times{10}^{-19}}$

=>n =$\dfrac{ 1\times {10}^{-7+19} }{ 1.6 }$

=>n = $\dfrac{ 1\times {10}^{12}}{ 1.6 }$

=> n = $0.625\times {10}^{12}$

=> n = $6.25\times {10}^{11}$

Hence the total number of electrons on the metal is $6.25\times {10}^{11}$

Remember

The charge present in any object is given by $n\times e$

where =>

n = number of electrons

e = charge present on one electron