please solve it urgently please...
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2tan30/1-tan^2 30 = tan60
2(1/√3)/1-(1/√3)^2 = √3
(2/√3)/(1-1/3) = √3
(2/√3)/(2/3) = √3
2/√3 × 3/2 = √3
3/√3 = √3
3 = √3×√3
3 = 3
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HOPE THIS Will HELP YOU
2(1/√3)/1-(1/√3)^2 = √3
(2/√3)/(1-1/3) = √3
(2/√3)/(2/3) = √3
2/√3 × 3/2 = √3
3/√3 = √3
3 = √3×√3
3 = 3
0
HOPE THIS Will HELP YOU
ksmarkogmailcom1:
thank u
but photo me solve karke bhej sakte ho
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HOPE IT HELPS. ............THANK YOU.
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