Math, asked by ksmarkogmailcom1, 1 year ago

please solve it urgently please...

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Answered by srajan452
1
2tan30/1-tan^2 30 = tan60
2(1/√3)/1-(1/√3)^2 = √3
(2/√3)/(1-1/3) = √3
(2/√3)/(2/3) = √3
2/√3 × 3/2 = √3
3/√3 = √3
3 = √3×√3
3 = 3
0

HOPE THIS Will HELP YOU

ksmarkogmailcom1: thank u
ksmarkogmailcom1: but photo me solve karke bhej sakte ho
Answered by deepunadkat06
1
HOPE IT HELPS. ............THANK YOU.
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