please solve it urgently please...
Attachments:
Answers
Answered by
1
2tan30/1-tan^2 30 = tan60
2(1/√3)/1-(1/√3)^2 = √3
(2/√3)/(1-1/3) = √3
(2/√3)/(2/3) = √3
2/√3 × 3/2 = √3
3/√3 = √3
3 = √3×√3
3 = 3
0
HOPE THIS Will HELP YOU
2(1/√3)/1-(1/√3)^2 = √3
(2/√3)/(1-1/3) = √3
(2/√3)/(2/3) = √3
2/√3 × 3/2 = √3
3/√3 = √3
3 = √3×√3
3 = 3
0
HOPE THIS Will HELP YOU
ksmarkogmailcom1:
thank u
Answered by
1
HOPE IT HELPS. ............THANK YOU.
Attachments:
Similar questions
Chemistry,
7 months ago
Physics,
7 months ago
Social Sciences,
1 year ago
Music,
1 year ago
Math,
1 year ago