Question

please solve it very very fast please​

Answer 1

the angel of the Quadrilator is Angel BGE is 105° , Angel GBF is 95°, Angel BFE is 75° and Angel GEF is 95°

Step-by-step explanation:

Given : AB || CD|| EF

angel ABG = 10°

angel DCE= 95°

angel BFE=75°

To Find: All the angles of Quadrilator BGEF

angle BGE =?

angle GEF=?

angel BFE=?

angel GBF= ?

Solution: It's given that AB||CD||EF

we know that opposite angle of the Quadrilator is 180° .

so, Angel BGE + Angel BFE = 180°

Angel BGE + 75°= 180°

Angel BGE= 105°

let's take AB||EF and BF as a transversal line.

Angel ABF + Angel BFE = 180° ( Co-Interior angel)

Angel ABF + 75°= 180°

Angel ABF = 180°- 75°

Angel ABF = 105°

we know that ..

Angel ABF = Angel ABG + Angel GBF

105° = 10° + Angel GBF

Angel GBF =95°

We also know that Sum of the angles of the Quadrilator is 360°

Angel BGE + Angel GEF + Angel BFE + Angel GBF = 360°

105° + Angel GEF +75° + 95° = 360°

Angel GEF + 275°= 360°

Angel GEF = 95°

Hence, the angel of the Quadrilator is Angel BGE is 105° , Angel GBF is 95°, Angel BFE is 75° and Angel GEF is 95°