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the value of x is 13
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Answer:
x^3-(x+1)^2=2001
applying formula (a+b)^2=a^2+2×a×b+b^2
x^3-(x^2+2×x×1+1^2)=2001
x^3-(x^2+2x+1)=2001
x^3-x^2-2x-1=2001
x^3-x^2-2x=2001+1
x^3-x^2-x=2002÷2
x^3-x^2-x=1001
Step-by-step explanation:
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