Math, asked by Happy1a1a, 1 year ago

Please solve it with full explanation

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Answered by kkhhuu
1
It is similar to the below example.

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Answered by AyushKashyap
1
Let us assume on contrary that √3+√5 is a rational number.

Then there exists co-prime positive integers pand q such that

=> √3+√5=p/q
=> p/q-√3=√5
=> (p/q-√3)²=(√5)² {squaring on both sides}
=> p²/q² - 2√3/q×p + 3=5
=> p²/q² - 2=2√3/q×p
=> p²-2q²/q²=2p/q×√3 {taking LCM}
=> p²-2q²/2pq=√3
=> √3 {p,q are integers therefore,p²-2q²/2pq is rational}

but this contradicts the fact that√3 is irrational. so our assumption is wrong.
hence,√3+√5 is irrational




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