Question

please solve it with full method​

Answer 1

Given:

A two-digit number whose:

• Digit at one's place is double the digit at ten's place

•  Sum of digits is 6

To Find:

• A two digit number following above conditions

Solution:

Let the digit at one's place be x and digit at ten's place be y

Then, the number will be

✏ 10y+x

Now,

According to the question

↬ x=2y------------------------(1)

Also,

According to the question

↬ x+y=6

From (1)

$\longrightarrow\mathrm{2y+y=6}$

$\longrightarrow\mathrm{3y=6}$

$\longrightarrow\mathrm{y=\dfrac{\cancel{6}}{\cancel{3}}}$

$\longrightarrow\mathrm{y=2}$

On putting value of y in (1), we get

↬ x=2(2)= 4

Therefore, the required number is

↬ 10(2)+4= 20+4= 24

Hence, the required number is 24.

Answer 2

AnswEr

The required number is 24

Given

• The digit at one's place in two digit number is double the digit at ten's place.
• The sum of the digits is 6

To Find

• The two digit number consisting these digits .

Solution

Let us consider the digit at ten's place be x and one's place be y

Therefore, the number is

10x + y

According to first condition ,

$\sf{y = 2x}.............(1)$

And by the second condition we have ,

$\sf{x + y = 6}.............(2)$

Using the value of y in (2) we have

$\sf{x + 2x = 6} \\ \implies \sf3x = 6 \\ \implies \boxed{ \bold{\sf{x = 2}}}$

Now putting the value of x in (1) we have ,

$\sf{y = 2 \times 2}\\ \implies \boxed{\bold{\sf{y = 4}}}$

Thus the number is

$\sf10 \times 2 + 4 \\ \sf = 20 + 4 \\ \boxed{\bold{ = \sf 24}}$