Question

please solve it with process​

Answer 1

Hi bruh

Ninga Tamil ah?

Your answer ✌✌

1. if 69.64% of manganese is there in 100% of  the compound, then in 100 g there will be 69.64 g of manganese in 100 g of the compound

Now, the amount of oxygen will be: 100 - 69.64 = 30.36 g of oxygen is present

Now, take the ratio of the mass of the element and their molar mass

Molar mass of Mn = 55

Molar mass of O = 16

$\frac{69.64}{55}$  = 1.26

$\frac{30.36}{16}$ = 1.89

Now, take the ratio between these two numbers

1.26 : 1.89 = 2 : 3

=> 2 atoms of Mn and 3 atoms of O are present in the oxide of the compound

So, your answer is: Mn₂O₃

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