Please Solve it With step.........
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(1³+2³+3³.............n³)= [ n(n+1/2 ] ²
To prove the above statement first compare the relationship between cube and square
cubes; answer; square; answer;
1³ 1 1² 1
1³+2³ 1+8=9 3² 9
1³+2³+3² 1+7+27 6² 36
=36
consider n as 1 ;
n³ = [ n(n+1) ] ²
1³ = [ 1(1+1²)]²
= [ 1 ( 2/2 ) ] ²
= 1×1
= 1
Hence,
Proved 1³+2³+3³...............n³= [ n(n+1)/2 ]²
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