Question

please solve it with steps

Answer 1

Mass(m) = 200 gm

= 2/10 kg

Time(t) = 60 sec

Latent heat of fusion(L) = 336 * 10³ J/kg

Specific heat capacity (c) = 4200 J/kg.K

Heat gained = m * L

= 2/10 * 336 * 10³

= 67200 J

Work done = Energy consumed

Work done = 67200 J

Power = Work/Time

= 67200/60

= 1120 J/s

Heat required = m * c * ∆t

= 2/10 * 4200 * (20-0)

= 16800 J

Work done = Energy consumed

Work done = 16800 J

Time = Work/Power

= 16800/1120

= 15 sec

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Answer 2

hope this is useful for you
by the way this is tooo good question