Question

please solve it with steps by step​

Answer 1

alpha + beta = -b/a

1/3 + beta = 10/3

beta = 10/3 - 1/3

beta = 9/3

beta = 3

Another zero is 3

alpha × beta = c/a

1/3×3 = c/3

3/3 = c/3 (on comparing)

c = 3 and hence p = 3.


Answer:- Option B

Answer 2

$HEYA \: \\ \\ in \: a \: general \: quadratic \: Equation \: say \\ ax {}^{2} + bx + c = 0 \: we \: have \\ \\ \alpha + \beta = - b \div a \\ and \\ \alpha \beta = c \div a \\ \\ here \: in \: \: 3x {}^{2} - 10 + p \\ \\ \alpha + \beta = 10 \div 3 \\ and \\ \alpha \beta = p \div 3 \\ \\ \alpha = 1 \div 3 \: \: \: (given \: ) \\ \\ (1 \div 3) + \beta = 10 \div 3 \\ \\ \beta = 3 \\ \\ (1 \div 3) \times (3) = p \div 3 \\ \\ p = 3 \\ \\ so \: \: the \: value \: of \: p \: is \: 3 \: and \: the \: other \: root \: is \: 3$