Question

please solve kar do.​jaldi

Answer 1

Answer:

The height of the wall is $\frac{8}{\sqrt{3} }$.

Step-by-step explanation:

Let the unknown height of the wall be x.

• tanθ = $\frac{opposite side}{adjacent side}$
• $tan30=\frac{x}{8}$

We know that

• $\frac{x}{8}= \frac{1}{\sqrt{3} }$

• $x = (\frac{1}{\sqrt{3} })(8)$

i.e $x=\frac{8}{\sqrt[2]{3} }$

Therefore, the height of the wall is  $\frac{8}{\sqrt{3} }$.

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Answer 2

Given :-

A ladder is placed against a wall of a house such that its upper end is touching the top of wall. The foot of the ladder is 8 m away from the foot of the wall and the ladder is making an angle of 30° with the level of ground

To Find :-

Height of the wall

Solution :-

We know that

tan A = Perp/Base

In ΔABC

∠ACB = 30°

BC = 8 m

tan A = AB/BC

⇒ tan(30) = AB/8

⇒ 1/√3 = AB/8

⇒ 8 × 1 = AB × √3

⇒ 8 = √3AB

⇒ 8/√3 = AB

⇒ 8 × √3/√3 × √3 = AB

⇒ 8√3/3 = AB

⇒ 8 × 1.732/3 = AB

⇒ 4.6 = AB

Hence,

Height of the wall is 8√3/3 or 4.6 m