Question

please solve last two

Answer 1

C3H8 + 10 O2 → 3CO2 +4 H2O
here 1 mole of propane react with oxygen to form CO2 and H2O
And A kJoule heat

question ask ,
2.4 litres how much heat produced
mole of propane = 2.4/22.4

so, heat of 2.4 Litres propane produced by combustion is
(2.4)/22.4 × A kj
= 2.4A/22.4


2) C + O2 → CO2
1 mole C react with 1 mole O2 to form 1 mole CO2 .

mole of C (graphite ) = 2.4× 10³/12 = 200

so, mole of O2 required = 200
so, mass of O2 = 200× 32 = 6400 = 6.4 kg

volume of O2 = 200× 22.4 L
= 4480 L

Answer 2

Answer:

hope my answer will help you