Question

please solve ldheorbdjrhrr
​

Answer 1

Step-by-step explanation:

Here ΔT

b

=373.16K−373.15K=0.01K, K

b

=0.5K/molkg, mass of water(solvent(W

1

))=100g=0.1kg, Molar mass of glucose(M

2

)=180.16g/mol

ΔT

b

=K

b

W

1

n

glucose

n

glucose

=

0.5K/molkg

0.01K×0.1kg

n

glucose

=2×10

−3

=

6.022×10

23

N

a

N

a

=12.046×10

20

Answer 2

Answer:

p*p q*q r*r

Step-by-step explanation:

ans is ready bye