Please solve my doubt... here the object distance is given as positive then image distance must be negative na..? C this ray diagram also here v tuk image down of the principal axis then according to sign conventions it must be negative na..?
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no the image size (which you would require in calculating magnification) is negative. v represents the image distance and hence since it is to the right of optical centre it is taken as positive.
GAnshu1:
but it is down of principal axis na
yeah that means image height is negative not the image distance
once consider the answer and apply mirrors formula accordingbto the information given in question... its getting different unless v take u is +ve
ohhkkk
tq so much
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ohhk i can do it only if anyother answer it.... definetly i will do bro
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