Physics, asked by GAnshu1, 1 year ago

Please solve my doubt... here the object distance is given as positive then image distance must be negative na..? C this ray diagram also here v tuk image down of the principal axis then according to sign conventions it must be negative na..?

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Answered by anthonyhowardstark

no the image size (which you would require in calculating magnification) is negative. v represents the image distance and hence since it is to the right of optical centre it is taken as positive.

GAnshu1: but it is down of principal axis na

anthonyhowardstark: yeah that means image height is negative not the image distance

GAnshu1: once consider the answer and apply mirrors formula accordingbto the information given in question... its getting different unless v take u is +ve

GAnshu1: ohhkkk

GAnshu1: tq so much

anthonyhowardstark: can you do me a fav and mark my answer as brainliest . Actually I joined brainly today and am already level 3. am not being able to upgrade bcuz I need to have 2 more brainliest answer. please help

GAnshu1: ohhk i can do it only if anyother answer it.... definetly i will do bro

anthonyhowardstark: thanks

Answered by venkyseela3112

Answer:

hiii

malli eppudu velthunnav clg ki

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