Question

please solve my dougt​

Answer 1

Step-by-step explanation:

perimeter of a rectangle is 2(l+b)

so,

2(6a²-4b²+a²+3ab)

2(7a²-4a²+3ab)

14a²-8b²+3ab

so,

the perimeter of rectangle is 14a²-8b²+3ab

Answer 2

Step-by-step explanation:

Given :-

The two adjacent sides of a rectangle are (6a²-4b²) and (a²+3ab)

To find :-

The perimeter of the rectangle.

Solution :-

Given that

The two adjacent sides of a rectangle are (6a²-4b²) units and (a²+3ab) units

We know that

Opposite sides are equal in a rectangle.

Therefore, All the four sides of the given rectangle will be (6a²-4b²) units , (a²+3ab) units ,(6a²-4b²) units and (a²+3ab) units

Let the length of the rectangle

= (6a²-4b²) units

Let the breadth of the rectangle

= (a²+3ab) units

We know that

Perimeter of a rectangle is 2(l+b) units

Perimeter of the given rectangle

=> P = 2[ (6a²-4b²)+(a²+3ab)]

=> P = 2(6a²-4b²+a²+3ab)

=> P = 2(7a²+3ab-4b²)

=> P = (14a²+6ab-8b²) units

Answer :-

The perimeter of the rectangle is (14a²+6ab-8b²) units

Used formulae:-

→ Opposite sides are equal in a rectangle.

→ Perimeter of a rectangle is 2(l+b) units

• l = length
• b = breadth