Question

Please solve my problem!!
​

Answer 1

$\large{\underbrace{\sf{\bf{\red{Required\:Answer}}}}}$

Let number of girls = 2x

and number of boys = 3x

Total students, 2x + 3x = 40

$\implies{\sf{x=8}}$

So, number of girls = $\displaystyle{\sf{ 2 \times 8 = 16}}$

and number of boys = = $\displaystyle{\sf{ 3\times 8 = 24}}$

Let out of 5 students, y denotes nunbder of boys.

Then, number of girls = 5-y

According to question,

$\displaystyle{\sf{ \dfrac{16+5-y}{24+y} = \dfrac{4}{5}}}$

$\implies{\sf{ 5(21-y) = 4(24+y) }}$

$\implies{\sf{ 105 - 5y = 96 + y}}$

Simplifying this equation.

$\large\implies{\boxed{\sf{\orange{ y = 1}}}}$

So, there must be one boy among five new students.

_____________________________

Answer 2

Answer:

yes

Step-by-step explanation:

hope you understand the above answer