Math, asked by Aartikhanna001, 1 month ago

Please solve my problem!!

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Answers

Answered by Rubellite
15

\large{\underbrace{\sf{\bf{\red{Required\:Answer}}}}}

Let number of girls = 2x

and number of boys = 3x

Total students, 2x + 3x = 40

\implies{\sf{x=8}}

So, number of girls = \displaystyle{\sf{ 2 \times 8 = 16}}

and number of boys = = \displaystyle{\sf{ 3\times 8 = 24}}

Let out of 5 students, y denotes nunbder of boys.

Then, number of girls = 5-y

According to question,

\displaystyle{\sf{ \dfrac{16+5-y}{24+y} = \dfrac{4}{5}}}

\implies{\sf{ 5(21-y) = 4(24+y) }}

\implies{\sf{ 105 - 5y = 96 + y}}

Simplifying this equation.

\large\implies{\boxed{\sf{\orange{ y = 1}}}}

So, there must be one boy among five new students.

_____________________________

Answered by rakeshsharmajbp01
0

Answer:

yes

Step-by-step explanation:

hope you understand the above answer

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