Question

please solve my problem.​

Answer 1

Step-by-step explanation: let the two digit no be 10x+y

according to the question:

10x+y + 10y+x=110.....1

(10x+y)-10=5(x+y)+4......2

on solving equation 1 and 2:

11x+11y=110

11(x+y)=110

x+y=10.........................3

(10x+y)-10=5x+5y+4

5x-4y=14......................4

now, on solving equation 3 and 4 we get:

x=8/3 and y=22/3

hence, 10x+y=10(8/3)+22/3

=102/3

=34

hence the first number is 34

Answer 2

Answer:

The first number is 64.

Step-by-step explanation:

Let the unit digit = y

Tens digit = x.

Original number = (10x+y)

After interchanging the digits the New number = (10y+x)

On adding the original number and reversed number we get,

(10x+y) + (10y+x) = 110

11x +11y = 110

11(x+y)= 110

x+y = 110/11

x+y= 10…………...(1)

x= 10-y……………(2)

on subtracting 10 from the original number , we get = 10x + y -10

and

4 more than 5 times the sum of digits

=5(x + y) + 4

So according to the question,

(10x+y) - 10 = 4+ 5(x+y)

(10x+y) - 10 = 4+ 5(10)

(10x+y) = 4+ 50+10

(10x+y) = 64

10(10-y) +y = 64

100-10y +y= 64

100 -9y = 64

-9y = 64-100

-9y = -36

y= 36/9= 4

y= 4

putting the value of y in eqn 2

x= 10-y

x= 10-4

x= 6

Hence , the first number is 6 & second number is 4.

Original Number is 10x+y

= 10× 6+4= 60+4= 64

Hope it helps! ! !