Question

please solve my problem B.1.

Answer 1

B1)

Height of object (h) = 1 cm

Radius of curvature = 20 cm

Focal length of convex mirror = R/2

= 20/2

=10 cm

Distance of object from mirror (u) = -20 cm

Distance of image from mirror (v) =?

Using mirror formula

$\implies \frac{1}{f} = \frac{1}{v} + \frac{1}{u}$


$\implies \: \frac{1}{ 10} = \frac{1}{v} + \frac{1}{ - 20}$


$\implies \: \frac{1}{ - 10} = \frac{1}{v } - \frac{1}{20}$


$\implies \: \frac{1}{ 10 } + \frac{1}{20} = \frac{1}{v}$


$\implies \: \frac{ 2 + 1}{20} = \frac{1}{v}$


$\implies \: \frac{ 3}{20} = \frac{1}{v}$


$\implies \: v = \frac{20}{3}$


Now, distance between object and image = u+v

$= - 20 + \frac{20}{3}$


$= \frac{ - 60 + 20}{3}$



$= \frac{ - 40}{3}$


Since, we are bothered about the distance, so the distance in cms between head of object to image is 40/3 cms. Hence, option C is correct.

Answer 2

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