Physics, asked by Anonymous, 1 year ago

please solve my problem B.1.

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gungunpatwal1: Hey

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Answered by SillySam

B1)

Height of object (h) = 1 cm

Radius of curvature = 20 cm

Focal length of convex mirror = R/2

= 20/2

=10 cm

Distance of object from mirror (u) = -20 cm

Distance of image from mirror (v) =?

Using mirror formula

$\implies \frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$\implies \: \frac{1}{ 10} = \frac{1}{v} + \frac{1}{ - 20}$

$\implies \: \frac{1}{ - 10} = \frac{1}{v } - \frac{1}{20}$

$\implies \: \frac{1}{ 10 } + \frac{1}{20} = \frac{1}{v}$

$\implies \: \frac{ 2 + 1}{20} = \frac{1}{v}$

$\implies \: \frac{ 3}{20} = \frac{1}{v}$

$\implies \: v = \frac{20}{3}$

Now, distance between object and image = u+v

$= - 20 + \frac{20}{3}$

$= \frac{ - 60 + 20}{3}$

$= \frac{ - 40}{3}$

Since, we are bothered about the distance, so the distance in cms between head of object to image is 40/3 cms. Hence, option C is correct.

SillySam: I completed all the demands of the question

SillySam: and you need to read the question once again... distance is asked between the *heads* of both not between the foot of image to head of object :)

SillySam: I think I am correct here ;) ... but if you are saying there must be some mistake... kindly make me do it :)

gungunpatwal1: hlo guys

priyanshu128855: yrr mujhe to abhi bhi meri calculation koi problem smjh m nhi aa rhi h

priyanshu128855: question m distance between the heads of the object and image puchi h and image to inverted bnegi to normal formulae se distance between the object and image nikalne se koi mtlb nhi h

Answered by rishu6845

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