Question

please solve my question​

Answer 1

Hey mate:)

Hope life's been amazing so far!!!

The fission of a single U235 nucleus releases 200 MeV of energy.

Energy released in the fission is given by the formula

E = 200 MeV = 200 × 106 × 1.6 × 10–19 = 3.2 × 10–11 Joule

P = nE/t

=> n/t = P/E = 103 / 3.2 × 10–11 = 3.125×1013

Hope I got it right:)

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Answer 2

❤Hola gm❤

number of fissions/ second= power/ energy/ fission

= 1/200 × 1.6 × 10^-13

= 1/ 3.2 × 10^-11

= 3.125 × 10^10

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