Question

please solve my question ​

Answer 1

Answer:

a. by SSS rule

b. yes by CPCT

Answer 2

A.

★To prove :-

∆EFG ≅ ∆HFG

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★Given that :-

EF=FH=3.5cm (Given)

EG=GH=4.2cm (Given)

FG=FG=5.5cm (Common)

Hence proved that ∆EFG ≅ ∆HFG(SSS)

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B.

∠EFG = ∠HFG (CPCT)

This means that FG bisects the angle ∠EFH.

As both of the angles are same and lie between the line segment FG too.

Hence Proved.

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I hope it helped you ✌.