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The area of the rhombus will be equal to

so total cost of painting will be

The area of the rhombus will be equal to
so total cost of painting will be
Answered by
0
Answer:
Rs 50√39= Rs 312.249
Step-by-step explanation:
Given,
Perimeter of Rhombus = 32
Perimeter of Rhombus = 4* side (adjacent side of the rhombus are equal)
therefore, 4*side = 32 m
Side = 32/4
Side = 8 m
One of the diagonal = 10 m
diagonal of the Rhombus bisect each other at right angle
So on making two diagonal 4 right angle triangles are formed
Consider one of the right angled triangle to find out the diagonal of the rhombus
Perpendicular = 5 m (half of 10 m)
Hypotenuse = 8 m
Base =?
Apply Pythagoras theorem,
H²= p²+b²
(8)² = 5²+b²
64-25 = b²
39 = b²
b = √39
Diagonal = 2√39
Area of the Rhombus= 1/2 * (product of two diagonal)
= 1/2*2√39*10
=10√39
Cost of painting = 5*10√39
= Rs 50√39 = Rs 312.249
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