Question

please solve my question

Answer 1

HOPE THIS WILL HELP YOU

The area of the rhombus will be equal to
$10 \sqrt{39}$
so total cost of painting will be
$2 \times 10 \sqrt{39} \times 5$

$100 \times 6.245 = 624.5rs$

Answer 2

Answer:

Rs 50√39=  Rs 312.249

Step-by-step explanation:

Given,

Perimeter of Rhombus = 32

Perimeter of Rhombus = 4* side (adjacent side of the rhombus are equal)

therefore, 4*side = 32 m

Side = 32/4

Side = 8 m

One of the diagonal = 10 m

diagonal of the Rhombus bisect each other at right angle

So on making two diagonal 4 right angle triangles are formed

Consider one of the right angled triangle to find out the diagonal of the rhombus

Perpendicular = 5 m (half of 10 m)

Hypotenuse = 8 m

Base =?

Apply Pythagoras theorem,

H²= p²+b²

(8)² = 5²+b²

64-25 = b²

39 = b²

b = √39

Diagonal = 2√39

Area of the Rhombus= 1/2 * (product of two diagonal)

= 1/2*2√39*10

=10√39

Cost of painting = 5*10√39

= Rs 50√39 = Rs 312.249