Question

please solve my question.​

Answer 1

Answer:

Hope it helps you.

Step-by-step explanation:

Answer :-

$\frac{4(2x+3)}{3} +\frac{4x}{5}=\frac{2x+1}{12} \\or \frac{4(2x+3)}{3} +\frac{4x}{5}-\frac{2x+1}{12} =0\\or \frac{(8x+12)}{3} +\frac{4x}{5}-\frac{2x+1}{12} =0\\or \frac{20(8x+12)+12(4x)-5(2x+1)}{60} =0\\or \frac{160x+240+48x-10x-5}{60} =0\\or \frac{208x-10x+235}{60} =0\\or \frac{198x+235}{60} =0\\or 198x+235=0\\or x=\frac{-235}{198}\\or x=-1\frac{37}{198}$

Answer 2

Step-by-step explanation:

-5/18 is the correct answer