Math, asked by ronakraj013, 3 days ago

please solve my question​

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Answers

Answered by miyanight
0

Answer:

8-2(2a-5)=2(a+3)-3a

We move all terms to the left:

8-2(2a-5)-(2(a+3)-3a)=0

We multiply parentheses

-4a-(2(a+3)-3a)+10+8=0

We calculate terms in parentheses: -(2(a+3)-3a), so:

2(a+3)-3a

We add all the numbers together, and all the variables

-3a+2(a+3)

We multiply parentheses

-3a+2a+6

We add all the numbers together, and all the variables

-1a+6

Back to the equation:

-(-1a+6)

We add all the numbers together, and all the variables

-4a-(-1a+6)+18=0

We get rid of parentheses

-4a+1a-6+18=0

We add all the numbers together, and all the variables

-3a+12=0

We move all terms containing a to the left, all other terms to the right

-3a=-12

a=-12/-3

a=+4

Answered by dibyajyotimondal1710
0

Answer:

8-4A+10=2A+6-3A

18-4A=6-A

12=3A

A=4

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