please Solve my question
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Let, The two equal angles be x°
And, Third angle be y°
Then,
y°=x°-18°=>x°-y°=18° .....(i)
Also,
2x°+y°=180° .....(ii)
Now,
Adding eq (i) and (ii), we get:-
2x°+y°+x°-y°=180°+18°
3x°=198°
x°=66°
So,
Two equal angles=x°=66°
Now,
y°=x°-18°=66°-18°=48°
Hope this helps you!
And, Third angle be y°
Then,
y°=x°-18°=>x°-y°=18° .....(i)
Also,
2x°+y°=180° .....(ii)
Now,
Adding eq (i) and (ii), we get:-
2x°+y°+x°-y°=180°+18°
3x°=198°
x°=66°
So,
Two equal angles=x°=66°
Now,
y°=x°-18°=66°-18°=48°
Hope this helps you!
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