Question

please solve my question

Answer 1

X + X + 1 + X + 2 = 999

3X + 3 = 999

3X + 3 - 3 = 999 - 3
3X = 996

3X/3 = 996/3
X = 332
Therefore, three consecutive integers that add up to 999 are:

332
333
334.....

Answer 2

Let,
First number be x
Second number be (x+1)
Third number be (x+2)
Then,
x+(x+1)+(x+2)=999
3x+3=999
3x=999-3
3x=996
x= 332
So,
First number= x= 332
Second number= (x+1)= 332+1= 333
Third number= (x+2)= 332+2= 334

Hope this helps you!