Question

please solve my question

Answer 1

let 1st part is X
another part is 153-X

ATQ
$x \times \frac{3}{5} =\: (153 - x) \times \frac{6}{7} \\ \frac{3x}{5} = \frac{918 - 6x}{7 } \\ 21x = 4590 - 30x \\ 51x = 4590 \\ x = 90$
one part is 90 and another part is (153-90)=63