please solve my question
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a)In Rhombus, perimeter=4×side
p=52,. a=52/4=13,a=13
By,the Pythagorean theorem,
h,square=side,square+side,square
13,square=12,square+side,square
169-144=25
=5,square
length of another side= 10
b)area=1/2×pq
=1/2×24×12
=120cm,square
p=52,. a=52/4=13,a=13
By,the Pythagorean theorem,
h,square=side,square+side,square
13,square=12,square+side,square
169-144=25
=5,square
length of another side= 10
b)area=1/2×pq
=1/2×24×12
=120cm,square
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