Question

please solve my question asap​

Answer 1

Step-by-step explanation:

Given Equations are :

$(1) \ \frac{ax}{cos\theta} + \frac{by}{sin\theta} = a^2 - b^2$

$(2) \ \frac{axsin\theta}{cos^2\theta} - \frac{bycos\theta}{sin^2\theta} = 0$

Equation (2) can be written as,

$(3) \ ax = (by) \ \frac{cos^3\theta}{sin^3\theta}$

Place Equation (3) in (1), we get

$\Rightarrow \ by \ \frac{cos^2\theta}{sin^3\theta} + \frac{by}{sin\theta} = a^2 - b^2$

$\Rightarrow by[\frac{cos^2\theta + sin^2theta}{sin^3\theta}] = a^2 - b^2$

$\Rightarrow by = (a^2 - b^2) \ sin^2\theta$

Now,

$\Rightarrow ax = (a^2 - b^2) = cos^3\theta$

Then,

$(ax)^{\frac{2}{3} } + (by)^{\frac{2}{3} }$

$\Rightarrow (a^2 - b^2)^{\frac{2}{3} } cos^3\theta+ (a^2 - b^2)^{\frac{2}{3}} sin^2\theta$

$\Rightarrow (a^2 - b^2)^{\frac{2}{3} }$

Hope it helps!

Answer 2

Answer:

ye question to aata na mere pe