Question

please solve my question correctly correctly correctly......don't spam......explanation must...​

Answer 1

7sin²Q+3cos²=9

TO PROVE tanQ=+-1/√3

7sin²Q+3cos²=9

7sin²Q+3(1-SIN²Q) =9

7sin²Q+3-3SIN²Q=9

4sin²Q=6

SIN²Q=6/4

SINQ=+-√3/2

SINQ=SIN π/6 and SINQ= SIN 4π/3

Q=π/6 and Q=4π/3

TANπ/6=1/√3 AND TAN 4π/3=-1/√3

tanQ=+-1/√3

PROVED