Please solve my question fast. URGENT!!!
From the figure given below, prove that ADC=A+B+C.
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Answer:
The proof is explained below.
Step-by-step explanation:
In the given figure ABCD, we have to prove that
∠A+∠B+∠C=∠ADC
Let us do construction: Join BD
In ΔABD,
By exterior angle property which states that an exterior angle of triangle is equal to the sum of opposite interior angles i.e
∠1+∠2=∠5 → (1)
Similarly in ΔCBD
∠4+∠3=∠6 → (2)
Adding equation (1)a nd (2), we get
∠1+∠2+∠4+∠3= ∠5 +∠6
⇒ ∠1+(∠2+∠3)+∠4=∠ADC
⇒ ∠A+∠B+∠C=∠ADC
Hence proved.
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sandhuSaaB1234:
good morning ji
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